In the reaction `AB_(2)(I) + 2X_(2) (g) hArr AX_(2) (g) + BX_(2) (g) Delta H = -270` k cal per mol. Of `AB_(2) (I)` the enthalpies of formation of `AX_(2) (g)` & `BX_(2) (g)` are in the ratio of `4 : 3` and have opposite sign. The value of `Delta H_(f)^(0) (AB_(2)(I)) = + 30` k cal/mol. Then

Options

A. `Delta H_(f)^(0) (AX_(2)) = - 96` kcal/mol
B. `Delta H_(f)^(0) (BX_(2)) = + 480` k cal/mol
C. `K_(P) = K_(c) " & " DeltaH_(f)^(0) (AX_(2)) = + 480 kcal//mol`
D. `K_(P) = K_(c) RT " & " DeltaH_(f)^(0) (AX_(2)) + Delta H_(f)^(0) (BX_(2)) = -240 kcal//mol`

Answer

C

Explanation

`AB_(2) (l) + 4X_(2) (g) hArr AX_(2) (g) + 2BX_(2) (g)`
`Delta H = -270, -270 = - 2(3x) + 4x -30`