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300K a gas (gamma = 5//3) is compressed ...

`300K` a gas `(gamma = 5//3)` is compressed adiabatically so that its pressure becomes `1//8` of the original pressure. The final temperature of the gas is :

A

420 K

B

300 K

C

`-142^(@)C`

D

`327^(@)C`

Text Solution

Verified by Experts

The correct Answer is:
C
In adiabatic process
`P_(1)^(1 - gamma) . T_(1)^(gamma) = P_(2)^(1 - gamma)=` constant
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