A piece of zinc at a temperature of 20...

A piece of zinc at a temperature of `20.0^(@)` C weighing 63.38 g is dropped into 180 g boiling water `(T= 100^(@)C`) . The specific heat of zinc is `0.400 Jg^(-1@) C` and that of water is `4.20 Jg^(1@) C` . What is the final common temperature reached by both the zinc and water ?

`97.3 .^(@)C`

`33.4 .^(@)C`

`80.1 .^(@)C`

`60.0 .^(@)C`

Text Solution

Verified by Experts

The correct Answer is:

`65.38 xx 0.4 (T - 293) = 180 xx 4.2 (373 - T)`

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