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Liquid water freezes at 273 K under exte...

Liquid water freezes at 273 K under external pressure of 1 atm. The process is at equilibrium `H_(2)O (I) hArr H_(2)O (s)` at 273 K & 1 atm However it was required to calculate the thermodyanamic parameters of the fusion prcess occuring at same pressure & different temperature. Using the following data, answer the question that follow.
`d_("ice") = 0.9 gm//c c, d_(H_(2)O(I)) = 1 gm//c c, C_(P) [H_(2)O(s)] = 36.4 JK^(-1) mol^(-1), C_(P) [H_(2)O (I) ] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1)`
`'' Delta S_("fusion")''` at 263 K & 1 atm will be:

A

`22.01 JK^(-1) mol^(-1)`

B

`22.84 JK^(-1) mol^(-1)`

C

`21.36 JK^(-1) mol^(-1)`

D

`20.557 JK^(-1) mol^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
D
`Delta_("fussion") S = (Delta_("fussion")H)/(T_(f))`
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Liquid water freezes at 273 K under external pressure of 1 atm. The process is at equilibrium H_(2)O (I) hArr H_(2)O (s) at 273 K & 1 atm However it was required to calculate the thermodyanamic parameters of the fusion prcess occuring at same pressure & different temperature. Using the following data, answer the question that follow. d_("ice") = 0.9 gm//c c, d_(H_(2)O(I)) = 1 gm//c c, C_(P) [H_(2)O(s)] = 36.4 JK^(-1) mol^(-1), C_(P) [H_(2)O (I) ] = 75.3 JK^(-1) mol^(-1), Delta H_("fusion") = 6008.2 J mol^(-1) The value of ''DeltaH_("fusion")'' at 263 K & 1 atm will be :

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