Home
Class 11
CHEMISTRY
For a reversible reaction at constant te...

For a reversible reaction at constant temperature and at constant pressure the equilibrium composition of reaction mixture corresponds to the lowest point on Gibbls energy Vs progress of reaction diagrams as shown. At equilibrium Gibbs energy of reaction is equal to zero.

The value of `"log"_(10) K_(eq)` is equal to [`k_(eq)` is the equilibrium coustant]

A

`- (Delta G^(@))/(RT)`

B

`(T Delta S^(@) - Delta H^(@))/(2.303 RT)`

C

`(Delta H^(@) - T Delta S^(@))/(RT)`

D

`(RT)/(T Delta S^(@) - Delta H^(@))`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta G^(0) = Delta H^(0) - T Delta S^(0) = - 2.303 RT` log Keq
Promotional Banner

Topper's Solved these Questions

  • THERMODYNAMICS

    NARAYNA|Exercise Passages|13 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Matching type|6 Videos

  • THERMODYNAMICS

    NARAYNA|Exercise Level -V|106 Videos

  • STRUCTURE OF ATOM

    NARAYNA|Exercise EXERCISE - IV EXEMPLAR PROBLEMS|24 Videos

Similar Questions

Explore conceptually related problems

For a reversible reaction at constant temperature and at constant pressure the equilibrium composition of reaction mixture corresponds to the lowest point on Gibbls energy Vs progress of reaction diagrams as shown. At equilibrium Gibbs energy of reaction is equal to zero. Which diagram represents the large value of equilibrium constant for the reversible reaction

For a reversible reaction at constant temperature and at constant pressure the equilibrium composition of reaction mixture corresponds to the lowest point on Gibbls energy Vs progress of reaction diagrams as shown. At equilibrium Gibbs energy of reaction is equal to zero. For a reaction M_(2)O_((s))^(3//4) rarr 2 M_((S)) + (1)/(2) O_(2 (g)) Delta H = 30 KJ//mol and Delta S = 0.07 KJ//mol //K at 1 atm. The reaction would not be spontaneous at temperature

In a reversible reaction, if the concentration of reactants are doubles, the equilibrium constant K will:

The equilibrium constant (K) of a reaction may be written as

If the equilibrium constant of a reaction is 2×10^3 at 25°C then the standard Gibbs free energy change for the reaction will be

The equilibrium constant of a reaction and the standard Gibbs energy change of the reaction are related by the equation

For a given reversible reaction at a fixed temperature, equilibrium constants K_(p) and K_(c) are related by ………