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For a reversible reaction at constant te...

For a reversible reaction at constant temperature and at constant pressure the equilibrium composition of reaction mixture corresponds to the lowest point on Gibbls energy Vs progress of reaction diagrams as shown. At equilibrium Gibbs energy of reaction is equal to zero.

For a reaction
`M_(2)O_((s))^(3//4) rarr 2 M_((S)) + (1)/(2) O_(2 (g)) Delta H = 30 KJ//mol` and `Delta S = 0.07 KJ//mol //K` at 1 atm. The reaction would not be spontaneous at temperature

A

`gt 428 K`

B

`gt 428 K`

C

`lt 100 K`

D

`gt 100 K`

Text Solution

Verified by Experts

The correct Answer is:
B
`Delta G^() = Delta H^(0) - T Delta S^(0) gt 0` for a non-spontaneous process
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