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Calculate the enthalpy change for the fo...

Calculate the enthalpy change for the following reversible process:
`alpha = T "in" hArr beta - T "in at" 13^(@)C`
1 mol at atm 1 mol at 1 atm
`(Delta H_("trans") = 2288 J mol^(-1))`

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The correct Answer is:
2
`Delta S_("trans") = (Delta H_("trands"))/(T) = (2288)/(286) = 8 J K^(-1) mol^(-1)`
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