How much heat is required to change `10g` ice at `0^(@)C` to steam at `100^(@)C`? Latent heat of fusion and vaporisation for `H_(2)O` are `80 cl g^(-1)` and `540 cal g^(-1)`, respectively. Specific heat of water is `1cal g^(-1)`.

Answer

7200 cal

Explanation

`Delta H_("total") = Delta H_("fusion") + Delta H_("heating") + Delta H_("vaporization")`
`10 xx 80 + 10 xx 1 xx 100 + 10 xx 540 = 7200 cal`