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Calculate DeltaH(f)^(@) for chloride ion...

Calculate `DeltaH_(f)^(@)` for chloride ion from the following data `:`
`(1)/(2)H_(2(g))+(1)/(2)Cl_(2(g))rarr HCl_((g)),DeltaH_(f)^(@)=-92.4kJ`
`HCl_((g))+nH_(2)O rarr H_((aq.))^(+)+Cl_((aq.))^(-),DeltaH^(@)=-74.8kJ`
`DeltaH_(f)^(@) H_((aq.))^(+)=0.0kJ`

Text Solution

Verified by Experts

The correct Answer is:
heat of formation for `Cl_(aq)^(-) = -167.2 kj`
Given , `(1)/(2)H_(2) (g) + aq. rarr H_(aq)^(+) +e`,
`Delta H^(0) = 0`....(i)
`(1)/(2) H_(2) (g) + (1)/(2) Cl_(2) (g) rarr HCl (g)`,
`Delta H^(0) = - 92.4 kJ`....(ii)
`HCl (g) + nH_(2)O (l) rarr H_((aq))^(+) + Cl_((aq))^(-)`,
`Delta H^(0) = -74.8 kJ`.....(iii) Add. eq. (ii) and (iii)
`(1)/(2) H_(2) (g) + (1)/(2) Cl_(2) (g) + nH_(2)O rarr H_((aq))^(+) + Cl_((aq))^(-)`,
`Delta H^(0) = -167.2 kJ`......(iv) Subtract eq. (i) from (iv)
`:. (1)/(2) Cl_(2) (g) + aq. + e rarr Cl_((aq))^(-), Delta H = -167.2 kJ`
Heat of formation for `Cl_(aq)^(-) = - 167.2 kJ`
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