An athelete is given `100g` of glucose `(C_(6)H_(12)O_(6))` of energy equivalent to `1560 kJ`. He utilises `50%` of this gained enegry in the event. In order to avoid storage of enegry in the body, calculate the weight of water he would need to perspire. The enthalpy of evaporation of water is `441kJ//mol`.

Answer

319.1g

Explanation

100 g glucose = 1560 kJ
Energy utilised left in body `= (50)/(100) xx 1560 = 780 kJ`
Hence energy to be given out `= 44 kJ//mol = 44 kJ//18 g` of water
Thus 44 kJ energy is given by water = 18 g 1 kJ energy is given by water `= 18//44 g` 730 kJ energy will be given by water `= (18)/(44) xx 780 = 319.1 g`
Hence amount water to be perspired to avid storage of energy = 319.1 g