The enthalpy change involved in the oxidation of glucose is `-2880kJ mol^(-1)`. Twenty five per cent of this energy is available for muscular work . If `100kJ` of muscular work is needed to walk one kilometre, what is the maximum distance that a person will be able to walk after eating `120g` of glucose ?

Answer

4.8 km

Explanation

Energy available for muscular work by 1 mole of glucose `= (2880 xx 25)/(100) = 720 kJ`
Thus, 180 g (1 mole) of glucose`(C_(6) H_(12) O_(6))` supplies energy = 720 kJ will supply 120 g glucose `= (720)/(180) xx 120 = 480 kJ`. Distance covered by 100 kJ energy = 1 km or 100 kJ is need to walk 1 km
`:.` Distance covered 480 kJ energy `= (1)/(100) 480 = 4.8 km`