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For the reaction 2CO +O(2) rarr 2CO(2)...

For the reaction
`2CO +O_(2) rarr 2CO_(2), DeltaH =- 560 kJ`,
`2mol` of `CO` and `1mol` of `O_(2)` are taken in a container of volume `1L`. They completely form `2 mol` of `CO_(2)`. The gaseous deviate appreciably from ideal behaviour. If the pressure in the vessel changes from `70` to `40atm`, find the magnetic (absolute) value of `DeltaU at 500K. (1 L-atm = 0.1 kJ)`

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The correct Answer is:
557 kj/mol
`Delta H = Delta U + V Delta P, ( :. Delta V = 0) , Delta U = Delta H - V Delta P`
`= - 560 - [0.1 (40 - 70) xx 0.1] = - 557 kJ` ltbr. So, the magnitude is `557 kJ mol^(-1)`
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