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A change in the free energy of a system ...

A change in the free energy of a system at constant temperature and pressure will be:
`Delta_(sys)G = Delta_(sys)H -T Delta_(sys)S`
At constant temperature and pressure
`Delta_(sys) G lt 0` (spontaneous)
`Delta_(sys)G = 0` (equilibrium)
`Delta_(sys)G gt 0` (non-spontaneous)
For a spontaneous reaction `DeltaG`, equilibrium `K` and `E_(cell)^(Theta)` will be, respectively

A

`-ve, gt 1, +ve`

B

`+ve, gt 1, -ve`

C

`-ve, lt 1, -ve`

D

`-ve, gt 1, -ve`

Text Solution

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The correct Answer is:
A
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