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Which of the following can not exhibit g...

Which of the following can not exhibit geometrical isomerism

A

`a_(2)C=Cb_(2)`

B

`abC=Cde`

C

`abC=Cab`

D

abC=Cda

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The correct Answer is:
To determine which of the given compounds cannot exhibit geometrical isomerism, we need to understand the conditions required for geometrical isomerism to occur. ### Step-by-Step Solution: 1. **Understanding Geometrical Isomerism**: - Geometrical isomerism occurs in compounds with a carbon-carbon double bond (C=C) where the two carbon atoms are bonded to different groups. The two main types of geometrical isomerism are cis-trans isomerism and E-Z isomerism. 2. **Identifying the Conditions**: - For geometrical isomerism to be possible, the following conditions must be met: - There must be a carbon-carbon double bond. - Each carbon of the double bond must be attached to two different substituents (groups). If both substituents on one carbon are the same, geometrical isomerism cannot occur. 3. **Analyzing the Options**: - Let's consider the four options provided: - **Option A**: C=C with two identical groups (e.g., A and A). - **Option B**: C=C with one A and one B on one carbon, and one B and one E on the other carbon. - **Option C**: C=C with one A and one B on one carbon, and one A and one B on the other carbon. - **Option D**: C=C with one A, one B, and one D on one carbon and one E on the other carbon. 4. **Evaluating Each Option**: - **Option A**: Since both groups on one carbon are the same (A and A), this compound cannot exhibit geometrical isomerism. - **Option B**: This compound has different groups on both carbons (A, B on one side and B, E on the other), allowing for geometrical isomerism. - **Option C**: This compound also has the same groups (A and B) on both sides, allowing for geometrical isomerism. - **Option D**: This compound has all different groups (A, B, D on one side and E on the other), allowing for geometrical isomerism. 5. **Conclusion**: - The only option that cannot exhibit geometrical isomerism is **Option A**, where both substituents on one carbon are identical. ### Final Answer: **Option A** cannot exhibit geometrical isomerism.
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