A compound contains 2 dissimilars asymmetric carbon atoms. The number of optically active isomers is

Options

A. 2
B. 3
C. 4
D. 5

Explanation

To determine the number of optically active isomers for a compound containing 2 dissimilar asymmetric (chiral) carbon atoms, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Number of Chiral Carbons**:
- The problem states that there are 2 dissimilar asymmetric carbon atoms in the compound. This means there are 2 chiral centers.

2. **Use the Formula for Optically Active Isomers**:
- The formula to calculate the number of optically active isomers is given by \(2^n\), where \(n\) is the number of chiral centers.
- In this case, \(n = 2\).

3. **Calculate the Number of Isomers**:
- Substitute \(n\) into the formula:
\[ 2^n = 2^2 = 4 \]
- Therefore, the number of optically active isomers is 4.

4. **Conclusion**:
- The compound has a total of 4 optically active isomers.

### Final Answer:
The number of optically active isomers is **4**.

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