sin2A+sin2B-sin2C=4cos A cos B sin C=

If A, B, C are angles of a triangle , prove that sin 2A+sin 2B-sin 2C=4cos Acos B sin C

If A+B+C=pi , prove that sin 2A+sin 2B-sin 2C=4 cos A cos B sin C

If A + B + C= pi , prove that sin 2A + sin 2B -sin 2C =4cos A cos B sin C

If A+B+C=180^(@), show that sin2A-sin2B-sin2C=-4sin A cos B cos C

If A+B+C=pi then prove that sin2A-sin2B+sin2C=4cos A sin B cos C

If A+B+C=pi/2 prove the following (i) sin 2A+sin 2B +sin 2C=4 cos A cos B cos C (ii) cos 2A +cos 2B+cos 2C=1+4 sin A sin B sin C.

If A+B+C= (pi)/(2) , then show that sin 2A+sin 2B +sin 2C=4 cos A cos B cos C

(sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=((lambda)/(2))(cos A)/(2)(cos B)/(2)(cos C)/(2) then lambda=

In a triangle ABC if (sin2A+sin2B+sin2C)/(cos A+cos B+cos C-1)=((lambda)/(2))cos((A)/(2))cos((B)/(2))cos((C)/(2)) then lambda equals

If A + B + C = (pi)/(2) , prove that sin 2A + sin 2B + sin 2C = 4 cos A cos B cos C