" Factorius "x^(3)-6x^(2)+3x+10

Using factor theorem,factorize x^(3)-6x^(2)+3x+10

If one root of x^3 -6x^2 +3x +10 =0 is 2 then the remaining two roots are

Find (dy)/(dx) , if y=(6x^(3)-3x^(2) -9x)^(10)

If the fraction (x^(3)+(a-10)x^(2)-x+a-6)/(x^(3)+(a-6)x^(2)-x+a-10) reduces to a quotient of two functions then a equals

If the fraction (x^(3)+(a-10)x^(2)-x+a-6)/(x^(3)+(a-6)x^(2)-x+a-10) reduces to a quotient of two functions,then a equals

If (x+5) is the HCF of (x^(2)+2x3b) and (6x^(3)+ax^(2)+3x-10), then a-2b=

Divide each of and find the quotient and remainder: 6x^(3)-x^(2)-10x-3by2x-3

Given that 2 is a root of x^3-6x^2+3x+10=0 , find the other roots .

Given that 2 is a root of x^3-6x^2+3x+10=0 , find the other roots .