(x-2)^(100)=sum_(r=0)^(100)a_(r)x^(r)"then "a_(1)+2a_(2)

If (1+x+x^(2))^(n)=sum_(r=0)^(2n)a_(r)x^(r), then a_(1)-2a_(2)+3a_(3)-...-2na_(2n)=

(1+x-2x^(2))^(6)=sum_(r=0)^(12)a_(r)x^(r) then a_(2)+a_(4)+....+a_(12)=

If (1+x-2x^(2))^(6)=sum_(r=0)^(12)a_(r).x^(r) then a_(1)+a_(3)+......a_(11)

If (1+x+x^(2))^(n) = sum_(r=0)^(2 n) a_(r). x^(r) then a_(1)-2 a_(2)+3 a_(3)-..-2 n. a_(2n) =

Let (1 + x + x^(2))^(100)=sum_(r=0)^(200)a_(r)x^(r) and a=sum_(r=0)^(200)a_(r) , then value of sum_(r=1)^(200)(ra_(r))/(25a) is

If (1+2x+x^(2))^(n) = sum_(r=0)^(2n)a_(r)x^(r) , then a_(r) =

If (1+2x+x^(2))^(n) = sum_(r=0)^(2n)a_(r)x^(r) , then a_(r) =

If (1+2 x+x^(2))^(n)=sum_(r=0)^(2 n) a_(r) x^(r) , then a_(r) =

If (1-x-x^(2))^(20)=sum_(r=0)^(40)a_(r).x^(r), then

If (n) is an odd positive integer and (1+x+x^(2)+x^(3))^(n) = sum_(r=0)^(3 n) a_(r) x^(r) then, a_(0)-a_(1)+a_(2)-a_(3)+.. .-a_(3 n) =