[x+2y+1=0],[2x-3y-12=0]

Solve the following system of equations by method of cross-multiplication: x+2y+1=0,quad 2x-3y-12=0

2(2x+y+5)+3(x-3y-1)=0 2x-3y+1=0

All points lying inside the triangle formed by the points (1.3).(5,0) and (-1,2) satisfy (A)3x+2y>=0 (B) 2x+y-13>=0 (C) 2x-3y-12 =0

If the equations 2x+3y+1=0,2x+y-1=0 and ax+2y-b=0 are consistent, then

(a) Using integration, find the area of the region bounded by the triangle whose sides are : (i) 3x-y-3=0, 2x+y-12=0, x-2y-1=0.

Using the method of integration, find the area of the region bounded by the following lines 3x -y-3=0, 2x+y-12=0, x-2y-1=0 .

For the circle x^(2)+y^(2)-2x-4y-4=0 ,the lines 2x+3y-1=0,2x+y-1=0 are

Find the solution of the pair of equations: x-y+1=0, 3x+2y-12=0

Solve for x and y: 2x - 3y-13 =0 , 3x -2y+12 =0