Find the slope of the tangent to the curve `y = x^3- x` at `x = 2`.

Explanation

To find the slope of the tangent to the curve \( y = x^3 - x \) at \( x = 2 \), we will follow these steps:

### Step 1: Differentiate the function
We need to find the derivative of the function \( y = x^3 - x \) with respect to \( x \).

\[ \frac{dy}{dx} = \frac{d}{dx}(x^3) - \frac{d}{dx}(x) \]
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