sqrt(4)" If "sin x+cos x=sqrt(y+(1)/(y)),1in|0,pi|," then "

If sin x+cos x=sqrt(y+(1)/(y)) for x in[0,pi] then x=(pi)/(4) (b) y=0y=1 (d) x=(3 pi)/(4)

If cos (pi/12) = (sqrt(2) + sqrt(6))/(4) , then all x in (0,pi/2) such that (sqrt(3)-1)/(sin x) + (sqrt(3)+1)/(cos x) = 4sqrt(2) , then find x.

If cos (pi/12) = (sqrt(2) + sqrt(6))/(4) , then all x in (0,pi/2) such that (sqrt(3)-1)/(sin x) + (sqrt(3)+1)/(cos x) = 4sqrt(2) , then find x.

If tan ^(-1) x + tan ^(-1) .sqrt( 1 - y^(2))/y = pi/3 " and " sin^(-1) y - cos^(-1) ( x/(sqrt( 1 + x^(2)))) = pi/6 " , then " ( 5 sin^(-1) x)/( sin^(-1) y) is

If tan ^(-1) x + tan ^(-1) .sqrt( 1 - y^(2))/y = pi/3 " and " sin^(-1) y - cos^(-1) ( x/(sqrt( 1 + x^(2)))) = pi/6 " , then " ( 5 sin^(-1) x)/( sin^(-1) y) is

The area of the region bounded by the curves y=sqrt((1+sin x)/(cos x)) and y=sqrt((1-sin x)/(cos x)) bounded by the lines x=0 and x=(pi)/(4) is

If y=cot^(-1)[(sqrt(1+sin x)+sqrt(1-sin x))/(sqrt(1+sin x)-sqrt(1-sin x))](0