free Cerem 2y y -3 और (iv) = -1 + X - 2 3 3

Factorise : (iv) (2x - y)^(3) - (2x - y)

(x)/(2)+(2y)/(3)=-1 And x-(y)/(3)

3x+2y=8 2x-3y=1

if y=3x+6x^(2)+10x^(3)+............ then the value of x in terms of y is (i) 1-(1-y)^(-(1)/(3))( ii) 1-(1+y)^((1)/(3))( iii) 1+(1+y)^(-(1)/(3))( iv )1-(1+y)^(-(1)/(3))

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))

Draw the graph for the following: (i) y=2x (ii) y=4x-1 (iii) y=((3)/(2)) x+3 (iv) 3x+ 2y =14

Solve the following pair of linear equations by the elimination method:(iv) x/2+(2y)/3=-1 and x-y/3=3