=4" If it "(5sin theta-3cos theta)/(sin theta+2cos theta)

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If 5tan theta=4, then (5sin theta-3cos theta)/(5sin theta+2cos theta) is equal to 0 (b) 1 (c) (1)/(6)(d)6

if 5cot theta=4, then the value of ((5sin theta-3cos theta)/(sin theta+2cos theta))

If 5 tan theta =4, find the value of (5 sin theta - 3 cos theta)/(5 sin theta +2 cos theta)

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )=

If theta lies in the first quadrant and 5 tan theta = 4 , " then " (5 sin theta - 3 cos theta )/( sin theta + 2 cos theta )= .............. A) 0 B) 1 C) 1/6 D) 5/14