(b)(999)^(3)

((999)^(3)-1)/((999)^(2)-1)=?

Evaluate: (999)^(3)

(12.999)^(3)=?

Evaluate (i) (102)^3 (ii) (999)^3

Using binomial therom find the value: (999)^(3)

Using binomial theorem, evaluate : (999)^(3) .

Evaluate (999)^(1//3) upto 4 places of decimal.

Evaluate each of the following using suitable identities : (999)^(3)

(999(1)/(7)+999(2)/(7)+999(3)/(7)+999(4)/(7)+999(5)/(7)+999(6)/(7)) is simplified to (a)2997(b)5979(c)5994(d)5997