If `A = [[cos^2theta, costhetasintheta],[costhetasintheta, sin^2theta]]` B= `[[cos^2phi, cosphisinphi], [cosphisinphi, sin^2phi]]` and `theta - phi = (2n+1)(pi)/2` Find AB.

If AB=O for the matrices A=[[cos^2theta,costhetasintheta],[costhetasintheta,sin^2theta]] and B=[[cos^2phi,cosphisinphi],[cosphisinphi,sin^2phi]] then theta-phi is

If theta-phi=pi/2, then show that [[cos^2theta,costhetasintheta],[costhetasintheta,sin^2theta]]*[[cos^2phi,cosphisinphi],[cosphisinphi,sin^2phi]]=0

Flind the product of two matrices A =[[cos^(2) theta , cos theta sin theta],[cos theta sin theta ,sin^(2)theta]] B= [[cos^(2) phi,cos phi sin phi],[cos phisin phi,sin^(2)phi]] Show that, AB is the zero matrix if theta and phi differ by an odd multipl of pi/2 .

If A=[(cos^2theta,costheta sintheta),(cos theta sintheta, sin^2theta)] and B=[(cos^2 phi, cos phi sin phi),(cos phisinphi,sin^2phi)], show that AB is zero matrix if theta and phi differ by an odd multiple of pi/2.

If theta-phi=pi/2, prove that, [(cos^2 theta,cos theta sin theta),(cos theta sin theta,sin^2 theta)] [(cos^2 phi,cos phi sin phi), (cos phi sin phi,sin^2 phi)]=0

If A=[[cos theta, sin theta],[sin theta, cos theta]],B=[[cos phi, sin phi],[sin phi, cos phi]] show that AB=BA.