Figures show a uniform magnetic field B condfirned to ta cylinderical bolume of radius R. If B is increasing aty constant rate of 0.01T/s. Instantaneous acceleration experienced by electron at r=10cm (ltR) as shown in the figure.

Options

A. `8.79xx10^(-12)m//s^(2)`
B. v`8.79xx10^(-11)m//s^(2)`
C. `8.79xx10^(-10)m//s^(2)`
D. `8.79xx10^(-09)m//s^(2)`

Answer

D

Explanation

`E(2pir) = pir^(2)(db)/(dt)rArr E= (1)/(2)r (dB)/(dt)`
`a=(eE)/(m_(e))= ((e)/(2)r((dB)/(dt)))/(m_(e))=(1.6 xx 10 ^(-19)xx(1)/(2) xx 0.1 xx0.01)/(9.1 xx 10^(-3))`
`8.79 xx 10^(-11) m//s^(2)`