If in a triode valve amplification factor is 20 and plate resistance is `10 kOmega` , then its mutual conductance is

Options

A. 2 milli mho
B. 20 milli mho
C. (1/2) milli mho
D. 200 milli mho

Answer

A

Explanation

Amplificantion factor `mu= 20`
Plante resistance `R_(p)= 10 K Omega = 10 xx 10 ^(-3) Omega`
`therefore` Mutual conductance `g_(m)= (mu)/(R_(p))`
` = (20)/( 10 xx 10^(3))`
`= 2 xx 10 ^(3) " mho or 2 milli mho "`