Water flows along horizontal pipe whose cross-section is not constant. The pressure is 1 cm of Hg, where the veloecity is 35 cm/s . At a point where the velocity is 65cm/s then pressure will be

Options

A. `0.89 cm of Hg`
B. `89 cm of Hg`
C. `0.5 cm of Hg`
D. `1 cm of Hg`

Explanation

To solve the problem, we will use Bernoulli's equation, which relates the pressure, velocity, and height of a fluid flowing in a pipe. The equation is given by:

\[ P_1 + \frac{1}{2} \rho v_1^2 + \rho g h_1 = P_2 + \frac{1}{2} \rho v_2^2 + \rho g h_2 \]

Since the pipe is horizontal, the height terms (h1 and h2) will be the same, and we can ignore them. Therefore, we can simplify the equation to:

\[ P_1 + \frac{1}{2} \rho v_1^2 = P_2 + \frac{1}{2} \rho v_2^2 \]

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