A block of mass m and density p is hanging from a string . If it is lowered into a vessel of cross-sectional area A containing a liquid of density `sigma(lt rho)` and gets fully immered, the increase in pressure at the bottom of vessel would be

Options

A. `(mrhog)/(sigma A)`
B. `(mrhog)/(rho A)`
C. `(mg)/(A)`
D. zero

Explanation

Volume of block `=(m)/(rho)`
`:.` Boutant force on block - Volume `xx` Density of liquid `xxg =(m)/(rho)xxsigmaxxg`
By Newtom's third law of motion, force exerted by block on liquid surface `=(msigmag)/(rhoA)`
`:.` Increases in pressure `=(msigmag)/(rhoA)`