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In an experiment to measure the internal...

In an experiment to measure the internal resistance of a cell by a potentiometer, it is found that the balance point is at a length of `2 m` when the cell is shunted by a `5 Omega` resistance and is at a length of `3 m` when the cell is shunted by a `10 Omega` resistance, the internal resistance of the cell is then

A

`12 Omega`

B

`8 Omega`

C

`16 Omega`

D

`1 Omega`

Text Solution

Verified by Experts

The correct Answer is:
B

As, `((1-2)/(2))4=((1-3)/(3))8 implies l=6`
Therefore, `r=((1-2)/(2))4=8 Omega`
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