Two positively charged particles each having charge `Q` and are `d` distance apart. A third charge is introduced in midway on the line joining the two charges. Find the nature and magnitude of third charge so that the system is in equilibrium.

Options

A. `q=(Q)/4`
B. `q=Q/4`
C. `q=(3Q)/4`
D. `q=-(3Q)/4`

Explanation

(a) Condition for equilibrium
`(kQ^(2))/(d^(2))+(kqQ)/((d//2)^(2))=0implies(kQ)/(d^(2))(Q+4q)=0`
`q=(-Q)/4`