A charge of `1muC` is divided into two parts such that their charges are in the ratio of `2:3`. These two charges are kept at a distance `1m` apart is vacuum. Then, the electric force between them (in `N`) is

Options

A. `0.216`
B. `0.00216`
C. `0.0216`
D. `2.16`

Explanation

(b) Ratio of charges `=2:3`
`:. q_(1)=2/5xx5xx1 mu C` and `q_(2)=35xx1 muC`
Electrostatic force between the two charges
`F=1/(4pi epsilon_(0))(q_(1)q_(2))/(r^(2))`
`=(9xx10^(9)xx2xx10^(-6)xx3xx10^(-6))/(5xx5xx(1)^(2))`
`=2.16xx10^(-3)N`
`~~0.00216N`