The equation of a sound wave in air is P = 0.01 cos (1000t-3xx) where P, x and t are in SI. The bulk modulus of elasticity is `1.4xx10^(5) N//m^(2)` the displacement amplitude is
A
0.24 m
B
`0.24xx10^(-7)m`
C
`8xx10^(-7)m`
D
10 m
Text Solution
Verified by Experts
The correct Answer is:
B
The standard equation is `" "p=p_(o)cos(omegat-x)` The given equation is `p=0.01cos (1000t-3x)` Comparing the Eq. (i) and Eq. (ii), we get `" "p_(o)=0.01N//m^(2)` `" "omega=1000red//s` `" "K=3` per meter But `" "p_(o)=` BAK `therefore" "A=(p_(0))/(BK)` [B=Bulk modulus of elasticity ] `=(0.01)/(14xx10^(5)xx3)=0.2381xx10^(-7)m~~0.24xx10^(-7)m`
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