When two waves of aimost equal frequenies `n_(1)` and `n_(2)` are produced simultaneously, then the time interval between successive mixima is
A
`1/(n_(1)-n_(2))`
B
`1/n_(1)-1/n_(2)`
C
`1/n_(1)+1/n_(2)`
D
`1/(n_(1)+n_(2))`
Text Solution
Verified by Experts
The correct Answer is:
A
Number of beats per second `=n_(1)-n_(2)` `therefore` Time interval between two succsesive maxima `=1/(n_(1)-n_(2))`
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