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The apparent frequency is f(1) when a so...

The apparent frequency is `f_(1)` when a souece of sound approches a stationary obsever with a speed u and `f_(2)` when the observe approaches the stationary source with same speed. If v is the velocity of sound, then

A

`f_(1)=f_(2)`

B

`f_(1) gt f_(2) if u ltv`

C

`f_(2) gt f_(1) if u ltv`

D

`f_(2) gt f_(1) if u ltv`

Text Solution

Verified by Experts

The correct Answer is:
D
`f_(1)=((v)/(v-v_(s)))f=((v)/(v-v))f=[((1)/(1-u/v))]f`
When observer approaches towards the source
`f_(2)=((v+v_(o))/(v))f=((v+u)/(v))f=(1-u/v)f`
`therefore" "f_(2) gt f_(1)`
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