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When a sound wave of wavelength lamda is...

When a sound wave of wavelength `lamda` is propagating in a medium, the maximum velocity of the particle is equal to the velocity. The ampilitude of wave is

A

`lamda`

B

`lamda/2`

C

`lamda/(2lamda)`

D

`lamda/ (4lamda)`

Text Solution

Verified by Experts

The correct Answer is:
C
`v_(max)= v rArrAomega=v rArr Axx2piv=vlamdaor A=lamda/(2pi)`
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