In an experiment with sonometer a tuning frok of frequency 256 Hz reaonates with a length of 25 cm and another tuning frok resonates with a length of 16 cm. Tension of the string remaining counstant the frequency to the second tuning fork is
A
163.84 Hz
B
400.Hz
C
320 Hz
D
204.8 Hz
Text Solution
Verified by Experts
The correct Answer is:
B
For sonometer, `nprop1/l` `therefore(n_(1))/(n_(2))=(l_(2))/(l_(1)) rArr(256)/(n_(2))=n_(2)=(256xx25)/(16)=400 Hz`
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