Home
Class 12
PHYSICS
Hubble's law is expressed as [v= speed o...

Hubble's law is expressed as [v= speed of recession, r=distance r of galaxy, H=Hubble constant]

A

v=`Hr^(2)`

B

v=Hr

C

`v=(H)/(r)`

D

`v=(H)/(r^(2))`

Text Solution

Verified by Experts

(b)
Promotional Banner

Topper's Solved these Questions

  • SOUND WAVES

    BITSAT GUIDE|Exercise BITSAT Archives|1 Videos

Similar Questions

Explore conceptually related problems

Hubble's law is related with

Dimensions of Hubble's constant are

Hubble constant is rate of

When the light emitted by a distant galaxy is spectrographically analysed, it is found to contain the characteristic patterns of radiation emitted by famoliar elements, but their wavelength show a red shift of 2% . How fast is the galaxy receding away from us? Using Hubble's law estimate the distance of galaxy in light year. Take Hubble's constant H=17kms^(-1) for every million light year.

According to Hubble's law, the redshift (Z) of a receding galaxy and its distance r from earth are related as

In Physics, what is Hubble Constant?

A ody is in pure rotation. The linear speed v of a particle, the distance r of the particle from the axis and the angular velocity omega of the body are related as omega=v/r . Thus

Consider a galaxy moving away from us with a speed of 6480kms^(-1) . It is a at a distance of 430 million light year from us, determine Hubble's constant H and corresponding age of universe t_(0)