In a triangle `ABC, CD` is the bisector of the angle C. If `cos (C/2)` has the value `1/3 and l(CD)=6,` then `(1/a+1/b)` has the value equal to -

In a triangle ABC, CD is the bisector of the angle C. If cos (C/2) has the value 1/3 and 1(CD)=6, then (1/a+1/b) has the value equal to -

In a triangle A B C ,\ C D is the bisector of the angle Cdot If cosC/2 has the value 1/3 and l(C D)=6, then (1/a+1/b) has the value equal to 1/9 (b) 1/(12) (c) 1/6 (d) none

If in a triangle ABC,CD is the angular bisector of the angle ACB then CD is equal to

In trianle ABC, CD is the bisector of the angle C. if cos . C/2 = 1/3 and CD = 6, then the value of (1/a + 1/b) = 1/lambda , " then " lambda is

In a triangle ABC,/_A=60^(@) and b:c=(sqrt(3)+1):2 then (/_B-/_C) has the value equal to

ABC is equilateral triangle and CD is the internal bisector of angle C . If DC is produced to E such that AC= CE , then angle CAE is equal to

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is

In a triangle ABC, D is a point on BC such that AD is the internal bisector of angle A . Let angle B = 2 angle C and CD = AB. Then angle A is