Home
Class 12
MATHS
The slope of the normal to the curve y=2...

The slope of the normal to the curve `y=2x^2+3`sin x at `x = 0`is(A) 3 (B) `1/3` (C)`-3` (D) `-1/3`

Text Solution

AI Generated Solution

To find the slope of the normal to the curve \( y = 2x^2 + 3\sin x \) at \( x = 0 \), we will follow these steps: ### Step 1: Differentiate the function We need to find the derivative of the function \( y \) with respect to \( x \) to get the slope of the tangent line. Given: \[ y = 2x^2 + 3\sin x ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The slope of the normal to the curve y=2x^(2)+3sin x at x=0 is :

Find the slope of the normal to the curve to y=x^(3)-x+1 at x=2.

Find the slope of the normal to the curve : y=x^(3)-x+1" at "x=2

Find the equation of the normal to the curve y=2x^(2)+3sin x at x=0.

The slope of the tangent line to the curve y=x^3-2x+1 at x=1 is

The slope of the normal to curve y= x^(3) - 4x^(2) at (2 , -1) is

Find the equation of the normal to the curve y=2x^(3)+3 sin x" at "x=0 .

Find the slopes of the tangent and the normal to the curve y=2x^2+3sinx at x=0

Write the slope of the normal to the curve y=1/x at the point (3,1/3)

The equation of normal to the curve y=3x^(2)-x+1 at (1,3) is