6+2=quad " s."2x-1=14-x

The locus of the centre of a circle which touches externally the circle x^(2)+y^(2)-6x-6y+14=0 and also touches Y-axis,is given by the equation (a) x2-6x-10y+14=0 (b) x2-10x-6y+14=0 (c) yr 6x-10y+14-0 (d) y,2-10x-6y+14=0

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x2-6x-10y+14 = 0 (b) x2-10x-6y + 14 = 0 (c) yr_6x-10y+14-0 (d) y,2-10x-6y + 14 = 0

Let us find the equation the radical axis of the circles S -= x^2 + y^2 - 5x + 6y + 12 =0 and S^1 -= x^2 + y^2 + 6x - 4y - 14 = 0

If the HCF of x^(2)-x-6 and x^(2)+9x+14 is (x+m) . Then the value of m is

The equation of the plane passing through the point 1,1,1) and perpendicular to the planes 2x+y-2z=5a n d3x-6y-2z=7, is 14 x+2y+15 z=3 14 x+2y-15 z=1 14 x+2y+15 z=31 14 x-2y+15 z=27

If 2^(2x)-2^(x-1)=14 then x^(x) is equal to

The domain of the function f(x) = sqrt(x^(14) - x^(11) + x^(6) - x^(3) + x^(2) + 1) is

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x^2-6x-10y+14 = 0 (b) x^2-10x-6y + 14 = 0 (c) y^ 2-6x-10y+14-0 (d) y^2-10x-6y + 14 = 0

The locus of the centre of a circle which touches externally the circle x^2 + y^2-6x-6y+14 = 0 and also touches Y-axis, is given by the equation (a) x^2-6x-10y+14 = 0 (b) x^2-10x-6y + 14 = 0 (c) y^2+6x-10y+14-0 (d) y^2-10x-6y + 14 = 0