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Evaluate: sin{tan^(-1)(7/(24))}...

Evaluate: `sin{tan^(-1)(7/(24))}`

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`tan^(−1)x=sin^(−1)(x/(sqrt(1+x^2))) `
`tan^(−1)(7/(24))=sin^(−1)(7/(25))`, and hence,
`sin(tan^(−1)(7/(24)))=sin(sin^(−1)(7/(25)))=7/(25)`
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