Number of all possible enols of formula `C_(4)H_(8)O` are :

Answer

12

Explanation

`CH_(2)=CH-CH_(2)-overset(OH)overset(|)CH-H to(1)`
`CH_(3)-underset(H)underset(|)C=underset(H)underset(|)C=overset(OH)overset(|)CH_(2) to (2) "geometrical isomer"`
`CH_(3)-CH_(2)-underset(H)underset(|)C=overset(OH)overset(|)C-H to(2)"geometrical"`
`CH_(2)=overset(OH)overset(|)C-CH_(2)-CH_(3) to(1)`
`CH_(2)=CH-underset(H)underset(|)overset(OH)overset(|)C"_(**)CH_(3) to (2) `enantiomer
`CH_(3)-underset(H)underset(|)C=overset(OH)overset(|)C-CH_(3)-(2)` geometrical
`H_(2)C=underset(CH_(3))underset(|)C=overset(OH)overset(|)C-H to (1)`
`HC_(3)=underset(CH_(3))underset(|)C=overset(OH)overset(|)C-H to (1)`