[" In "/_ABC,B-D=C" and "BD" ,"BC=20" then pird "],[" mollowing ratios "]

In DeltaABC ,B - D - C and BD = 7, BC = 20, then find following rations. (A(DeltaADC))/(A(DeltaABC))

In DeltaABC , B - D - C and BD = 7, BC = 20 , then find following rations. (A(DeltaADC))/(A(DeltaABC))

In DeltaABC,B-D-C and BD=7, BC=20 , then find followig ratios: (A(DeltaABD))/(A(DeltaADC)) (A(DeltaABD))/(A(DeltaABC)) (A(DeltaADC))/(A(DeltaABC))

In DeltaABC ,B - D - C and BD = 7, BC = 20, then find the ratio (A(DeltaABD))/(A(DeltaABC))

In DeltaABC , B - D - C and BD = 7, BC = 20 , then find the ratio. (A(DeltaABD))/(A(DeltaADC))

In DeltaABC , B - D - C and BD = 7, BC = 20 , then find the ratio (A(DeltaABD))/(A(DeltaABC))

In DeltaABC ,B - D - C and BD = 7, BC = 20, then find the ratio. (A(DeltaABD))/(A(DeltaADC))

In Delta ABC, if B=60^@,C=45^@ and D divides BC internally in the ratio 1:3 then (sinangleBAD)/(sinangleCAD) =

In /_ABC,AB=AC and D is any point on BC , prove that AB^(2)-AD^(2)=BD.CD