Solve : `4sin^(-1)x=pi-cos^(-1)x`

Explanation

To solve the equation \( 4\sin^{-1}x = \pi - \cos^{-1}x \), we can follow these steps:

### Step 1: Rewrite the equation
We start with the equation:
\[ 4\sin^{-1}x = \pi - \cos^{-1}x \]
We know that \( \cos^{-1}x + \sin^{-1}x = \frac{\pi}{2} \). Therefore, we can express \( \cos^{-1}x \) in terms of \( \sin^{-1}x \):
...