Prove that : `tan^(-1)2+tan^(-1)3=(3pi)/4`

Explanation

To prove that \( \tan^{-1}(2) + \tan^{-1}(3) = \frac{3\pi}{4} \), we can use the formula for the sum of inverse tangents. The formula states:

\[ \tan^{-1}(x) + \tan^{-1}(y) = \tan^{-1}\left(\frac{x+y}{1-xy}\right) + n\pi \]

where \( n \) is an integer, and the formula applies under certain conditions based on the signs of \( x \) and \( y \) and the product \( xy \).

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