`0.40 g` of an organic compound (A), `(M.F.-C_(5)H_(8)O)` reacts with x mole of `CH_(3)MgBr` to liberate 224 mL of a gas at STP. With excess of `H_(2)`, (A) gives pentan-1-ol. The correct structure of (A) is :
mol. Mass of `A = 12 xx 5 + 8+16 = 84g` moles of `A = (0.40g)/(84 g) = 0.005 "moles"` moles of gas released at STP `= (224 mL)/(22.4 L) = 0.01 "moles"` `:. 0.005` moles of A release 0.01 moles of gas . i.e., ratio of 1:2. Hence there must be acidic H in the compound A. One acidic H is from alcohol the other must be terminal alkynes as only the H attached to terminal alkynes are acidic. `A overset("Excess" H_(2))rarr "pentan"-1-ol` Hence option (d) is incorrect.
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MS CHOUHAN-GRIGNARD REAGENTS-Level 1 (Q.61 To Q.66)
