" zero at infinity,the potential at xis "

The gravitational field due to a mass distribution is E=(A)/(x^(2)) in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x is

The gravitational field due to a mass distribution is E=(A)/(x^(2)) in x-direction. Here, A is a constant, Taking the gravitational potential to be zero at infinity, potential at x is

The gravitational field due to a mass distribution is given by vec(l)=(k)/(x^(2))hat(i) , where k is a constant. Assuming the potential to be zero at infinity, find the potential at a point x = a.

The gravitational field due to a mass distribution is given by vec(l)=(k)/(x^(2))hat(i) , where k is a constant. Assuming the potential to be zero at infinity, find the potential at a point x = a.

A proton and an antiproton come close to each other in vacuum such that the distance between them is 1.0 cm. Consider the potential energy to be zero at infinity. The velocity at this distance will be