Reaction of `RCONH_(2)` with a mixture of `Br_(2)` and `KOH` gives `RNH_(2)` as the main product. The intermediates involved in the reaction are:

Options

A. `R-overset(OH)overset(|)(C)=N-Br`
B. `R-NHBr`
C. `R-N=C=O`
D.

Answer

To solve the problem, we need to analyze the reaction of an amide (RCONH₂) with a mixture of bromine (Br₂) and potassium hydroxide (KOH) to determine the intermediates involved in the process. The main product of this reaction is an amine (RNH₂).

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
The reaction described is known as the Hofmann rearrangement, which involves the conversion of an amide to an amine with the loss of one carbon atom.

2. **Starting Material**:
The starting material is an amide, RCONH₂. In the presence of Br₂ and KOH, the amide undergoes a rearrangement.

3. **Formation of an Intermediate**:
The first step involves the formation of an intermediate. When RCONH₂ reacts with Br₂ in a basic medium (KOH), the bromine will react with the nitrogen atom of the amide. This leads to the formation of an N-bromoamide (RCONHBr).

4. **Formation of Carbamic Acid**:
The N-bromoamide can further react in the presence of water (from the KOH solution) to form an intermediate known as carbamic acid (R-NHCOOH). This is where the nitrogen is bonded to a carbonyl group (C=O) and has a hydroxyl group (OH).

5. **Final Product Formation**:
The carbamic acid can then decompose to yield the final product, which is an amine (RNH₂) and carbon dioxide (CO₂). The nitrogen atom in the carbamic acid loses a carbon atom during this rearrangement, resulting in the formation of the amine.

6. **Identify the Intermediates**:
Based on the steps above, the intermediates involved in the reaction are:
- N-bromoamide (RCONHBr)
- Carbamic acid (R-NHCOOH)

However, the question specifically asks for the intermediates involved, and among the options given, the correct intermediate that fits the description is R-N-C-O (which represents the carbamic acid structure).

### Conclusion:
The main intermediate involved in the reaction is **R-N-C-O**, which corresponds to the carbamic acid formed during the reaction.

### Final Answer:
The correct answer is **C: R-N-C-O**.

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