`CH_(3)CH_(2)Br overset(AgCN)rarr A overset(NaOH, Delta)underset(overset(o+)(H_(3)O))rarrB,(B)` is:

Options

A. `CH_(3)CH_(2)NHCH_(3)`
B. `CH_(3)CH_(2)CH_(2)NH_(2)`
C. `CH_(3)CH_(2)NH_(2)`
D.

Answer

To solve the given question step by step, we will analyze the reactions involved:

### Step 1: Reaction of CH₃CH₂Br with AgCN
- **Starting Material**: CH₃CH₂Br (Bromoethane)
- **Reagent**: AgCN (Silver Cyanide)

When bromoethane reacts with silver cyanide, the bromine atom is replaced by a cyanide group. The reaction can be represented as follows:

\[ \text{CH}_3\text{CH}_2\text{Br} + \text{AgCN} \rightarrow \text{CH}_3\text{CH}_2\text{N} \equiv \text{C} + \text{AgBr} \]

Here, AgBr is formed as a byproduct, and the main product is isocyanide (or carbylamine), which is represented as CH₃CH₂N≡C.

### Step 2: Hydrolysis of Isocyanide in Basic Medium
- **Intermediate Product**: CH₃CH₂N≡C (Isocyanide)
- **Reagents**: NaOH (Sodium Hydroxide) and H₃O⁺ (Hydronium ion)

Next, the isocyanide undergoes hydrolysis when treated with NaOH and then with H₃O⁺. The hydrolysis of isocyanide leads to the formation of a primary amine:

\[ \text{CH}_3\text{CH}_2\text{N} \equiv \text{C} + \text{H}_2\text{O} \xrightarrow{\text{NaOH, } \Delta} \text{CH}_3\text{CH}_2\text{NH}_2 + \text{CO}_2 \]

The final product after hydrolysis is ethylamine (CH₃CH₂NH₂).

### Conclusion
Thus, the final product B is:

\[ \text{B} = \text{CH}_3\text{CH}_2\text{NH}_2 \]

### Answer
The correct answer is option C: CH₃CH₂NH₂ (Ethylamine).

---